Mohali T20: India beat South Africa by 7 wickets

In the T20 match played between India and South Africa in Mohali, India has defeated the visiting team by seven wickets.

South Africa scored 149 runs in the prescribed 20 overs at the loss of 5 wickets.

India achieved this target by losing three wickets and remaining one over.

The Indian team started off chasing the goal was not very good.

The first wicket fell in the third over as Rohit Sharma. At that time India's score was 33 runs. Rohit Sharma scored 12 runs.
The second wicket fell on a score of 94 runs. It was Bari Shikhar Dhawan who scored 40 runs. The third wicket fell in the 13th over. Pant was caught out after scoring four runs.

After this, Kohli and Iyer took over the front. Kohli scored an unbeaten 72 runs. Iyer also remained unbeaten after scoring 16 runs.

South Africa

Earlier, India won the toss and invited South Africa to bat.

South Africa had scored 149 runs losing 5 wickets in the prescribed 20 overs. Quinton Dickock scored the highest 52 runs.

Bavuma missed a half-century by one run and was caught by Jadeja off Chahar on a score of 49.

Miller contributed 18 and Pretorius contributed 10 runs. The remaining batsmen could not make more than eight runs.

The first T20 match between India and South Africa was to be held in Dharamshala, which had to be canceled due to rain.

India won the second T20 match played in Mohali.

The third T20 match between the two teams will be played at the M Chinnaswamy Stadium in Bengaluru on Sunday.

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Mohali T20: India beat South Africa by 7 wickets Mohali T20: India beat South Africa by 7 wickets Reviewed by Latest news paper on September 19, 2019 Rating: 5

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